To make a 750 -piece jigsaw puzzle more challenging, a puzzle company includes 5 extra pieces in the box along with the 750 pieces, and those 5 extra pieces do not fit anywhere in the puzzle. If you buy such a puzzle box, break the seal on the box, and immediately select 1 piece at random, what is the probability that it will be 1 of the extra pieces?

To determine the probability of selecting one of the extra pieces from the puzzle box, follow these steps: 1. **Total Number of Pieces:** - Regular puzzle pieces: 750 - Extra pieces: 5 - **Total pieces in the box:** \(750 + 5 = 755\) 2. **Number of Favorable Outcomes:** - The extra pieces that do not fit anywhere: 5 3. **Probability Calculation:** - The probability \(P\) of selecting an extra piece is the ratio of the number of extra pieces to the total number of pieces. \[ P = \frac{\text{Number of extra pieces}}{\text{Total number of pieces}} = \frac{5}{755} \] 4. **Simplify the Fraction:** - Divide both the numerator and the denominator by 5: \[ P = \frac{5 \div 5}{755 \div 5} = \frac{1}{151} \] So, the probability of randomly selecting one of the extra pieces is: \(\boxed{\dfrac{1}{151}}\)