Question 1 of 10 For what value of \( x \) is the rational expression below undefined? \[ \begin{array}{l}\frac{x-4}{4+x} \\ \text { A. }-1 \\ \text { B. } 4 \\ \text { C. } 0 \\ \text { D. } 4\end{array} \]

A rational expression is undefined when its denominator is equal to zero. In the given expression: \[ \frac{x-4}{4+x} \] we need to find the value of \( x \) that makes the denominator \( 4 + x \) equal to zero: \[ 4 + x = 0 \] To solve for \( x \), we can subtract 4 from both sides: \[ x = -4 \] However, the options provided are: - A. -1 - B. 4 - C. 0 - D. 4 None of these options include \( -4 \). Therefore, it seems there may be a mistake in the options provided. The correct answer is that the rational expression is undefined for \( x = -4 \).