Question 1 of 10 For what value of $$ x $$ is the rational expression below undefined? $$ \begin{array}{l}\frac{x-4}{4+x} \ \text { A. }-1 \ \text { B. } 4 \ \text { C. } 0 \ \text { D. } 4\end{array} $$

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A rational expression is undefined when its denominator is equal to zero. In the given expression:

$$
\frac{x-4}{4+x}
$$

we need to find the value of $$ x $$ that makes the denominator $$ 4 + x $$ equal to zero:

$$
4 + x = 0
$$

To solve for $$ x $$, we can subtract 4 from both sides:

$$
x = -4
$$

However, the options provided are:

- A. -1
- B. 4
- C. 0
- D. 4

None of these options include $$ -4 $$. Therefore, it seems there may be a mistake in the options provided.

The correct answer is that the rational expression is undefined for $$ x = -4 $$.
The rational expression is undefined for $$ x = -4 $$.

Question 1 of 10
For what value of is the rational expression below undefined?

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