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Exercice 1 1) Compléter avec l'un des symboles : \( \epsilon ; \notin ; \subset \) ou \( \notin \) \( \{0 ;-7 ; 12\} \ldots \ldots \mathbb{N}^{*} ; \frac{5 \pi-\pi}{2 \pi-\pi} \ldots . \mathbb{Q} ;\left\{-1 ; \frac{18}{6} ; \sqrt{36} ;-7\right\} \ldots . \mathbb{Z} ; \frac{7}{3} \ldots \ldots \) ID 2) donner l'écriture scientifique : \( A=\frac{4 \times 300^{2} \times\left(2 \times 10^{-6}\right)^{-2}}{(0.01)^{-3}} \)

Ask by Martinez Peters. in Morocco
Dec 24,2024

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**Exercice 1** 1) **Compléter avec les symboles :** a) \( \{0, -7, 12\} \notin \mathbb{N}^{*} \) b) \( \frac{5\pi - \pi}{2\pi - \pi} \in \mathbb{Q} \) c) \( \left\{-1, \frac{18}{6}, \sqrt{36}, -7\right\} \subset \mathbb{Z} \) d) \( \frac{7}{3} \in \mathbb{Q} \) **Exercice 2** 2) **Écriture scientifique de \( A \):** \( A = 9 \times 10^{10} \)

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Pour le premier exercice, voici les symboles appropriés : \( \{0 ; -7 ; 12\} \in \mathbb{N}^{*} ; \frac{5 \pi - \pi}{2 \pi - \pi} \notin \mathbb{Q} ; \{-1 ; \frac{18}{6} ; \sqrt{36} ; -7\} \subset \mathbb{Z} ; \frac{7}{3} \notin \mathbb{Z} \). Pour le deuxième exercice, on commence par simplifier l'expression : \[ A = \frac{4 \times 300^{2} \times (2 \times 10^{-6})^{-2}}{(0.01)^{-3}} \] Calculons chaque partie : - \( 300^{2} = 90000 \), - \( (2 \times 10^{-6})^{-2} = \frac{1}{4 \times 10^{-12}} = \frac{10^{12}}{4} \), - \( (0.01)^{-3} = (10^{-2})^{-3} = 10^{6} \). En réunissant tout : \[ A = \frac{4 \times 90000 \times \frac{10^{12}}{4}}{10^{6}} = \frac{90000 \times 10^{12}}{10^{6}} = 90000 \times 10^{6} = 9 \times 10^{10} \]. Donc l'écriture scientifique de \( A \) est \( 9 \times 10^{10} \).

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