h. $$ \frac{2 x}{x^{2}-y^{2}}+\frac{1}{x+y}-\frac{1}{x-y} $$

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Calculate or simplify the expression $$ \frac{2x}{x^2-y^2}+\frac{1}{x+y}-\frac{1}{x-y} $$.
Simplify the expression by following steps:
- step0: Solution:
  $$\frac{2x}{x^{2}-y^{2}}+\frac{1}{x+y}-\frac{1}{x-y}$$
- step1: Factor the expression:
  $$\frac{2x}{\left(x-y\right)\left(x+y\right)}+\frac{1}{x+y}-\frac{1}{x-y}$$
- step2: Reduce fractions to a common denominator:
  $$\frac{2x}{\left(x-y\right)\left(x+y\right)}+\frac{x-y}{\left(x+y\right)\left(x-y\right)}-\frac{x+y}{\left(x-y\right)\left(x+y\right)}$$
- step3: Rewrite the expression:
  $$\frac{2x}{\left(x-y\right)\left(x+y\right)}+\frac{x-y}{\left(x-y\right)\left(x+y\right)}-\frac{x+y}{\left(x-y\right)\left(x+y\right)}$$
- step4: Transform the expression:
  $$\frac{2x+x-y-\left(x+y\right)}{\left(x-y\right)\left(x+y\right)}$$
- step5: Calculate:
  $$\frac{2x-2y}{\left(x-y\right)\left(x+y\right)}$$
- step6: Factor the expression:
  $$\frac{2\left(x-y\right)}{\left(x-y\right)\left(x+y\right)}$$
- step7: Reduce the fraction:
  $$\frac{2}{x+y}$$
The simplified form of the given expression is $$ \frac{2}{x+y} $$.
The simplified form of the expression is $$ \frac{2}{x+y} $$.

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