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QUESTION 2 2.1 The arithmetic sequence \( 4 ; 10 ; 16 ; \ldots \) is the sequence of the first difference of a quadratic sequence with a first term equal to 3 . Determine the \( 50^{\text {th }} \) term of the quadratic sequence. 2.2 Given the finite arithmetic sequence \( 5 ; 1 ;-3 ; \ldots-83 ;-87 \) 2.2.1 Calculate the number of terms in the sequence 2.2.2 Calculate the sum of all the negative numbers in the sequence.

Ask by Rogers Garrett. in South Africa
Feb 03,2025

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**2.1:** The 50th term of the quadratic sequence is **7,255**. **2.2.1:** There are **24 terms** in the sequence. **2.2.2:** The sum of all negative numbers in the sequence is **−990**.

Solution

Let's tackle each part of **Question 2** step by step. --- ### **2.1. Determining the \( 50^{\text{th}} \) Term of the Quadratic Sequence** **Given:** - The first difference sequence is an arithmetic sequence: \( 4, 10, 16, \ldots \) - The first term of the quadratic sequence (\( S_1 \)) is **3**. **Steps:** 1. **Identify the Common Difference (\( d \)) of the First Difference Sequence:** \[ d = 10 - 4 = 6 \] 2. **Express the \( n^{\text{th}} \) Term of the First Difference Sequence (\( D_n \)):** \[ D_n = 4 + (n - 1) \times 6 = 6n - 2 \] 3. **Relate the First Difference to the Quadratic Sequence:** For a quadratic sequence \( S_n = an^2 + bn + c \), the first difference is: \[ S_{n+1} - S_n = 2an + a + b \] Setting this equal to the first difference sequence: \[ 2an + a + b = 6n - 2 \] 4. **Solve for \( a \) and \( b \):** - Compare coefficients: \[ 2a = 6 \Rightarrow a = 3 \] \[ a + b = -2 \Rightarrow 3 + b = -2 \Rightarrow b = -5 \] 5. **Determine the Constant Term (\( c \)) Using \( S_1 = 3 \):** \[ S_1 = 3(1)^2 - 5(1) + c = 3 - 5 + c = 3 \Rightarrow c = 5 \] 6. **Formulate the Quadratic Sequence:** \[ S_n = 3n^2 - 5n + 5 \] 7. **Calculate the \( 50^{\text{th}} \) Term (\( S_{50} \)):** \[ S_{50} = 3(50)^2 - 5(50) + 5 = 3(2500) - 250 + 5 = 7500 - 250 + 5 = 7255 \] **Answer:** The \( 50^{\text{th}} \) term of the quadratic sequence is **7,255**. --- ### **2.2. Working with the Finite Arithmetic Sequence \( 5, 1, -3, \ldots, -83, -87 \)** **Given:** - First term (\( a \)) = 5 - Second term = 1 → Common difference (\( d \)) = \( 1 - 5 = -4 \) - Last term (\( l \)) = -87 #### **2.2.1. Calculating the Number of Terms** **Formula:** \[ l = a + (n - 1)d \] **Plugging in the values:** \[ -87 = 5 + (n - 1)(-4) \] \[ -87 - 5 = -4(n - 1) \] \[ -92 = -4(n - 1) \] \[ n - 1 = \frac{-92}{-4} = 23 \] \[ n = 24 \] **Answer:** There are **24 terms** in the sequence. #### **2.2.2. Calculating the Sum of All Negative Numbers in the Sequence** **Identifying Negative Terms:** - The first two terms are positive (5 and 1). - From the 3rd term onwards, the terms are negative. - Number of negative terms = Total terms - 2 = 24 - 2 = 22 **First Negative Term (\( S_3 \)):** \[ S_3 = 5 + (3 - 1)(-4) = 5 - 8 = -3 \] **Last Term (\( S_{24} \)):** \[ S_{24} = -87 \] **Sum of Negative Terms (\( S_{\text{neg}} \)):** \[ S_{\text{neg}} = \frac{\text{Number of terms}}{2} \times (\text{First negative term} + \text{Last term}) \] \[ S_{\text{neg}} = \frac{22}{2} \times (-3 + (-87)) = 11 \times (-90) = -990 \] **Answer:** The sum of all negative numbers in the sequence is **−990**. --- ### **Final Summary** - **2.1:** The \( 50^{\text{th}} \) term of the quadratic sequence is **7,255**. - **2.2.1:** There are **24 terms** in the sequence. - **2.2.2:** The sum of all negative numbers in the sequence is **−990**.

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To determine the \(50^{\text{th}}\) term of the quadratic sequence, we first find the differences in the arithmetic sequence \(4; 10; 16; \ldots\) which gives a consistent second difference of \(6\). Since the first term of the quadratic sequence is \(3\) with a second difference of \(6\), we use the quadratic formula \(a_n = a + (n-1)d + \frac{(n-1)(n-2)}{2} \cdot c\) where \(c\) is half the second difference. Plugging in the values, we find the \(50^{\text{th}}\) term is calculated as: \[ a_{50} = 3 + (50 - 1) \cdot 4 + \frac{(50-1)(50-2)}{2} \cdot 3 = 3 + 196 + 1176 = 1375. \] Turning to the arithmetic sequence \(5; 1; -3; \ldots; -83; -87\), we spot that it starts at \(5\) and decreases by \(4\) each time. To find the number of terms, we set the last term \( -87 = 5 + (n-1)(-4)\), solve for \(n\), yielding \(n = 23\). For the sum of all negative numbers in this sequence, the negative numbers start from \(-3\) to \(-87\). The sequence of negative terms is \(-3, -7, -11, \ldots, -87\) and is an arithmetic sequence with the first term of \(-3\) and \(d = -4\). To find the number of terms, we solve for \(n\) in \(-87 = -3 + (n-1)(-4)\), resulting in \(n = 22 - 1\) or \(n = 22\). The sum is calculated using the formula for the sum of an arithmetic series \(S_n = \frac{n}{2} (a + l)\), for \(a = -3\), \(l = -87\), and \(n = 22\), thus, \[ S = \frac{22}{2}\left(-3 - 87\right) = 11 \cdot (-90) = -990. \]

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