A tennis ball may leave a top player's racket on the serve with a speed of 65.0 \( \mathrm{~m} / \mathrm{s} \). The ball's mass is 0.0600 kg and it is in contact with the racket for 0.0300 s . Assume the ball begins at rest. \( l \)

It appears you're working on a physics problem involving the motion of a tennis ball upon being hit by a racket. Based on the information provided: - **Mass of the ball (\( m \))**: 0.0600 kg - **Initial velocity (\( u \))**: 0 m/s (starts from rest) - **Final velocity (\( v \))**: 65.0 m/s - **Contact time (\( \Delta t \))**: 0.0300 s Assuming you're looking to find the **average force (\( F \))** exerted by the racket on the ball, here's how you can approach the problem: ### Step 1: Calculate the Change in Momentum (Impulse) The impulse experienced by the ball can be calculated using the formula: \[ \text{Impulse} = \Delta p = m \cdot \Delta v \] Where: - \( \Delta p \) is the change in momentum - \( m \) is the mass - \( \Delta v = v - u \) is the change in velocity Plugging in the values: \[ \Delta p = 0.0600 \, \text{kg} \times (65.0 \, \text{m/s} - 0 \, \text{m/s}) = 3.90 \, \text{kg} \cdot \text{m/s} \] ### Step 2: Determine the Average Force Impulse is also equal to the average force multiplied by the contact time: \[ \text{Impulse} = F_{\text{avg}} \cdot \Delta t \] Solving for \( F_{\text{avg}} \): \[ F_{\text{avg}} = \frac{\Delta p}{\Delta t} = \frac{3.90 \, \text{kg} \cdot \text{m/s}}{0.0300 \, \text{s}} = 130 \, \text{N} \] ### **Answer** The average force exerted by the racket on the tennis ball is **130  N**.