Question
The diagram shows a semi-circle with diameter
F of lenget
.
Angle
radians and the shaded region has an aree of Aem",
Show that
.
b Given that
is inereasing at a rate of 0.05 radians per second, find the tate of
change of
when
radians.
Angle
Show that
b Given that
change of
Ask by Gibbs Olson. in Bangladesh
Mar 23,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
When
, the rate of change of
is
.
Solution
To solve the problem, we will break it down into two parts:
Part a: Show that
-
Identify the components of the area
: - The area of the sector formed by angle
in a circle with radius is given by: - The radius
of the semi-circle is half of the diameter : - Therefore, the area of the sector is:
- The area of the sector formed by angle
-
Calculate the area of the triangle
: - The area of triangle
can be calculated using the formula: - The base
and the height can be found using the sine function: - Thus, the area of triangle
is:
- The area of triangle
-
Combine the areas:
- The area of the shaded region
is the area of the sector minus the area of the triangle:
- The area of the shaded region
-
Using the double angle identity:
- We can express
in terms of : - Therefore, we can rewrite the area as:
- This simplifies to:
- We can express
Part b: Find the rate of change of
when
-
Differentiate
with respect to time : - Using the chain rule:
- Using the chain rule:
-
Calculate
: - Differentiate
:
- Differentiate
-
Evaluate
at : - First, calculate
: - Therefore:
- First, calculate
-
Given
radians/second: - Now, calculate
:
- Now, calculate
-
Calculate the final result:
- Thus:
- Thus:
Final Answers:
- Part a:
- Part b: The rate of change of
when is .
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The Deep Dive
To find the area
of the shaded region in the semi-circle, we can divide it into two parts: the area of the sector formed by angle
and the area of the isosceles triangle
. The area of the sector is given by
where
m, so the sector area becomes
. The area of triangle
can be calculated using the formula
. Here
m (the diameter) and
, hence the triangle’s area is
. Therefore, combining both areas gives
and equating that correctly yields
.
To find the rate of change of
when
, we can use the chain rule. First, we differentiate
with respect to
. Given
rad/s, we find
. Thus, we first compute
. Deriving
, we get
. Evaluating this at
, we can substitute it back to find
. Hence, we have
. Multiplying by
gives us
.