Pregunta
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The diagram shows a semi-circle with diameter F of lenget .
Angle radians and the shaded region has an aree of Aem",
Show that .
b Given that is inereasing at a rate of 0.05 radians per second, find the tate of
change of when radians.

Ask by Gibbs Olson. in Bangladesh
Mar 23,2025

Solución de inteligencia artificial de Upstudy

Respuesta verificada por el tutor

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When , the rate of change of is .

Solución

To solve the problem, we will break it down into two parts:

Part a: Show that

  1. Identify the components of the area :
    • The area of the sector formed by angle in a circle with radius is given by:
    • The radius of the semi-circle is half of the diameter :
    • Therefore, the area of the sector is:
  2. Calculate the area of the triangle :
    • The area of triangle can be calculated using the formula:
    • The base and the height can be found using the sine function:
    • Thus, the area of triangle is:
  3. Combine the areas:
    • The area of the shaded region is the area of the sector minus the area of the triangle:
  4. Using the double angle identity:
    • We can express in terms of :
    • Therefore, we can rewrite the area as:
    • This simplifies to:

Part b: Find the rate of change of when

  1. Differentiate with respect to time :
    • Using the chain rule:
  2. Calculate :
    • Differentiate :
  3. Evaluate at :
    • First, calculate :
    • Therefore:
  4. Given radians/second:
    • Now, calculate :
  5. Calculate the final result:
    • Thus:

Final Answers:

  • Part a:
  • Part b: The rate of change of when is .

Respondido por UpStudy AI y revisado por un tutor profesional

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The Deep Dive

To find the area of the shaded region in the semi-circle, we can divide it into two parts: the area of the sector formed by angle and the area of the isosceles triangle . The area of the sector is given by where m, so the sector area becomes . The area of triangle can be calculated using the formula . Here m (the diameter) and , hence the triangle’s area is . Therefore, combining both areas gives and equating that correctly yields .
To find the rate of change of when , we can use the chain rule. First, we differentiate with respect to . Given rad/s, we find . Thus, we first compute . Deriving , we get . Evaluating this at , we can substitute it back to find . Hence, we have . Multiplying by gives us .

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