Find the roots of the factored polynomial. $$ \begin{array}{l}(x-2)^{3} \ \text { Write your answer as a list of values separated by commas, } \ x=\square\end{array} $$

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To find the roots of the factored polynomial $$(x-2)^3$$, we need to set the expression equal to zero and solve for $$x$$.

$$
(x-2)^3 = 0
$$

Since any number raised to the power of 3 that equals zero must be zero itself, we can solve for $$x$$ by setting the base equal to zero:

$$
x - 2 = 0
$$

Now, add 2 to both sides to solve for $$x$$:

$$
x = 2
$$

The root of the polynomial is $$x = 2$$. Since it's a cubic polynomial and the exponent is 3, the root $$x = 2$$ is a root of multiplicity 3. This means that $$x = 2$$ is the only root of the polynomial, and it occurs three times.

So, the roots of the polynomial are:

$$
x = 2
$$
x = 2

Find the roots of the factored polynomial.

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