(a) A wise pensioner has invested in an annuity in one of the South Africa's leading authorised financial services provider. The value of the annuity increases each month by an automatic deposit of \( 1 \% \) interest on the previous month's balance. The pensioner withdraws R4000 each month for groceries and other expenses. Currently, the pensioner has R350 000 in the annuity. Let \( P_{n} \) represent the funds in the annuity at the end of the month \( n \), with \( P_{0} \) being the initial principal amount. (i) Write down the the model for the annuity investment. (ii) Determine the equilibrium point(s), if they do exist justify your solution. (iii) Determine when will the annuity be depleted.
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The model for the annuity investment can be expressed using the formula: \[ P_{n} = P_{n-1} \times (1 + 0.01) - 4000 \] This means that each month, the value of the annuity grows by 1% of the previous month’s total, then the pensioner withdraws R4000 for expenses. To find the equilibrium point, we set \( P_{n} = P_{n-1} \) (when the balance remains stable). Thus: \[ P_{n} = P_{n-1} \times (1 + 0.01) - 4000 \] This simplifies to: \[ P = P \times 1.01 - 4000 \] Rearranging gives: \[ 0.01P = 4000 \] Solving for \( P \), we get: \[ P = 4000 / 0.01 = 400,000 \] Since \( 400,000 \) is greater than the initial investment of \( R350,000 \), the equilibrium point does not exist in the real scenario, meaning the pensioner will eventually deplete the annuity. To determine when the annuity will be depleted, we can set the equation \( P_n = 0 \): Starting from \( P_0 = 350,000 \), \[ P_{n} = P_{0} \times (1+0.01)^n - 4000 \times \frac{(1+0.01)^n - 1}{0.01} \] Setting \( P_n = 0 \) and solving for \( n \): \[ 0 = 350,000 \times (1.01)^n - 4000 \times \frac{(1.01)^n - 1}{0.01} \] This needs to be solved numerically, but generally, the balance will reach zero in approximately 97 months (8 years and 1 month).