Solve by graphing: \( \frac{3 x}{2 x-1}=2 x-3 \) \( \left\{-\frac{7}{20}, \frac{21}{10}\right\} \) \( \left\{-1, \frac{3}{4}\right\} \) \( \left\{\frac{3}{10}\right\} \) \( \left\{\frac{3}{10}, \frac{12}{5}\right\} \)
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To solve the equation \( \frac{3 x}{2 x-1}=2 x-3 \) by graphing, start by rearranging the equation into two separate functions. Let \( y_1 = \frac{3x}{2x - 1} \) and \( y_2 = 2x - 3 \). The solutions to the equation will occur where these two graphs intersect. Graphing \( y_1 \), you can see a hyperbola, with a vertical asymptote at \( x = \frac{1}{2} \). For \( y_2 \), it's a straight line with a slope of 2 that crosses the y-axis at -3. When you plot both on the same coordinate plane, you'll find the points of intersection represent the solutions: \( \left\{-\frac{7}{20}, \frac{21}{10}\right\} \) and others based on the nature of the functions. To ensure a clear understanding of where to look for solutions, remember to consider the domain restrictions, especially since \( 2x - 1 \) cannot equal zero (producing that vertical asymptote). This will help you avoid potential pitfalls like including invalid solutions. Happy graphing!