4) $$ \begin{array}{l}n(a)=3 a+2 \ f(a)=2 a-4 \ ext { Find }\left(\frac{g}{f} ight)(3)\end{array} $$ (3)

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4) $$ \begin{array}{l}n(a)=3 a+2 \ f(a)=2 a-4 \ 	ext { Find }\left(\frac{g}{f}ight)(3)\end{array} $$ (3)

UpStudy AI · Accepted Answer

It appears there might be a small typo in your problem statement. You've defined the functions $$ n(a) $$ and $$ f(a) $$, but the expression to evaluate is $$ \left(\frac{g}{f}\right)(3) $$. Assuming that $$ g(a) $$ was intended to be $$ n(a) $$, we can proceed as follows:

Given:
$$
n(a) = 3a + 2 \
f(a) = 2a - 4
$$

We need to find:
$$
\left(\frac{n}{f}\right)(3) = \frac{n(3)}{f(3)}
$$

First, calculate $$ n(3) $$:
$$
n(3) = 3(3) + 2 = 9 + 2 = 11
$$

Next, calculate $$ f(3) $$:
$$
f(3) = 2(3) - 4 = 6 - 4 = 2
$$

Now, compute the ratio:
$$
\frac{n(3)}{f(3)} = \frac{11}{2}
$$

**Answer:**  
$$\dfrac{11}{2}$$
$$\frac{11}{2}$$

4) \( \begin{array}{l}n(a)=3 a+2 \\ f(a)=2 a-4 \\ \text { Find }\left(\frac{g}{f}\right)(3)\end{array} \) (3)

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