6 Subtract these monomials: \( \begin{array}{lll}\text { a) } 8 x-3 x & \text { b) } 8 a-7 a & \text { c) } 11 x^{2}-6 x^{2} \\ \text { d) } 5 a^{2}-9 a^{2} & \text { e) } m^{3}-5 m^{3} & \text { f) } 4 n^{4}-n^{4} \\ \text { g) } \frac{5}{6} x-\frac{1}{6} x & \text { h) } \frac{3 a^{2}}{4}-\frac{1}{2} a^{2} & \text { i) } \frac{a^{3}}{2}-\frac{2 a^{3}}{5}\end{array} \)
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Sure, let’s subtract those monomials step by step: a) \(8x - 3x = 5x\) b) \(8a - 7a = 1a\) or just \(a\) c) \(11x^2 - 6x^2 = 5x^2\) d) \(5a^2 - 9a^2 = -4a^2\) e) \(m^3 - 5m^3 = -4m^3\) f) \(4n^4 - n^4 = 3n^4\) g) \(\frac{5}{6}x - \frac{1}{6}x = \frac{4}{6}x = \frac{2}{3}x\) h) \(\frac{3a^2}{4} - \frac{1}{2} a^2 = \frac{3a^2}{4} - \frac{2a^2}{4} = \frac{1a^2}{4} = \frac{a^2}{4}\) i) \(\frac{a^3}{2} - \frac{2a^3}{5} = \frac{5a^3}{10} - \frac{4a^3}{10} = \frac{1a^3}{10} = \frac{a^3}{10}\) And there you have it—subtracted! Keep practicing these, and soon you'll be a pro at working with monomials!