A student sets up the following equation to convert a measurement. (The? stands for a number the student is going to calculate.) Fill in the missing part of this equation. \( \left(-5.6 \times 10^{3} \frac{\mathrm{~g}}{\mathrm{~cm}^{3}}\right) \cdot \square=? \frac{\mathrm{~B}}{\mathrm{~m}^{3}} \)

To fill in the missing part of the equation, we need to convert grams per cubic centimeter (g/cm³) to bels per cubic meter (B/m³). We know that 1 g/cm³ is equal to 1000 kg/m³ and that 1 bel (B) is defined as the logarithm of the power ratio. So, using the conversion factors and relationships: \( 1 \frac{\mathrm{g}}{\mathrm{cm}^{3}} = 1000 \frac{\mathrm{kg}}{\mathrm{m}^{3}} \) To convert 1000 kg/m³ into B/m³, we can relate it back to the given measures and solve: We can hypothesize that \(\square\) is equal to \(1000 \ \frac{\mathrm{B}}{\mathrm{g/cm}^{3}}\) since converting g/cm³ to its corresponding value in B/m³ would require taking into account the necessary unit conversion. Thus, it becomes clear that \(\square\) should indeed hold that value. So the complete equation looks like: \( \left(-5.6 \times 10^{3} \frac{\mathrm{g}}{\mathrm{cm}^{3}}\right) \cdot (1000 \frac{\mathrm{B}}{\mathrm{g/cm}^{3}}) = ? \frac{\mathrm{B}}{\mathrm{m}^{3}} \)