To open a file with a user supplied name, you would need to store the name in a variable. If the file name was to have no more than 20 characters in it, which would be an appropriate declaration of the file name variable? char filename; char filename[21]; char filename[20];

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To store a file name with no more than 20 characters in C, you need to account for the null terminator (`\0`) that marks the end of a string. This means you should allocate an array that can hold 20 characters plus the null terminator, totaling 21 characters.

Here's a breakdown of the options:

1. **`char filename;`**
   - This declares a single character, which is insufficient for storing a file name.

2. **`char filename[21];`**
   - This declares an array of 21 characters, allowing for 20 characters in the file name plus the null terminator. This is the correct choice.

3. **`char filename[20];`**
   - This declares an array of 20 characters, which can only hold 19 characters of the file name plus the null terminator. This is not sufficient if the file name can be up to 20 characters long.

**Correct Declaration:**
```c
char filename[21];
```

This ensures that the file name can be safely stored without exceeding the allocated memory.

**Answer:** Use a character array of length 21, for example:
 char filename[21];
Use a character array of length 21, for example: char filename[21];

To open a file with a user supplied name, you would need to store the name in a variable. If the file name was to have no more than 20 characters in it, which would be an appropriate declaration of the file name variable? char filename; char filename[21]; char filename[20];

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