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1. Find the degree bf each term and the degree of the polynomial. \( \begin{array}{ll}\text { a. } 2 x^{2}+x-4 & \text { b. } 3 x^{2} y+\frac{x^{3}}{2}+\frac{7}{4}\end{array} \)

Ask by Cox Hardy. in the United States
Feb 13,2025

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Answer

a. The degrees of the terms are 2, 1, and 0. The polynomial degree is 2. b. The degrees of the terms are 3, 3, and 0. The polynomial degree is 3.

Solution

We need to examine each term, determine its degree, and then find the highest degree among the terms (which is the degree of the whole polynomial). a. For 2x² + x – 4:  • Term 1: 2x² has a degree of 2.  • Term 2: x is really 1·x¹, so its degree is 1.  • Term 3: –4 is a constant, with a degree of 0.  Thus, the polynomial’s degree is the highest degree among its terms, which is 2. b. For 3x²y + ½x³ + 7/4:  • Term 1: 3x²y involves x with exponent 2 and y with exponent 1, so its total degree is 2 + 1 = 3.  • Term 2: ½x³ has a degree of 3.  • Term 3: 7/4 is a constant and has a degree of 0.  Thus, the degree of this polynomial is also 3. Summary:  a. Degrees of terms: 2, 1, 0; Polynomial degree = 2.  b. Degrees of terms: 3, 3, 0; Polynomial degree = 3.

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Bonus Knowledge

For the polynomial \( 2x^{2} + x - 4 \), the degrees of the individual terms are \( 2 \) (for \(2x^2\)), \( 1 \) (for \(x\)), and \( 0 \) (for \(-4\)). The degree of the entire polynomial, which is the highest degree of its terms, is \( 2 \). In the polynomial \( 3x^{2}y + \frac{x^{3}}{2} + \frac{7}{4} \), the degrees of the individual terms are \( 3 \) (for \( \frac{x^3}{2} \)), \( 3 \) (for \( 3x^2y \) since \(2 + 1 = 3\)), and \( 0 \) (for \(\frac{7}{4}\)). The highest degree across the polynomial is also \( 3 \).

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