he function $$ h(x)=\frac{1}{x-5} $$ can be expressed in the form $$ f(g(x)) $$, where $$ g(x)=(x-5) $$, and $$ f(x) $$ is lefined as: $$ f(x)=\square $$

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Given the function 
$$
h(x)=\frac{1}{x-5},
$$
we want to express it as 
$$
h(x)=f(g(x))
$$
with 
$$
g(x)=x-5.
$$

Since 
$$
h(x)=\frac{1}{x-5} \quad \text{and} \quad g(x)=x-5,
$$
we substitute $$ g(x) $$ into $$ f $$ such that:
$$
f(g(x))=\frac{1}{g(x)}.
$$

This means that the function $$ f(x) $$ must be defined as:
$$
f(x)=\frac{1}{x}.
$$

Thus, the answer is:
$$
f(x)=\frac{1}{x}.
$$
$$ f(x) = \frac{1}{x} $$

he function can be expressed in the form , where , and is
lefined as:

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he function can be expressed in the form , where , and is lefined as: