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Question If \( C=y+5 \) and \( D=y^{2}-y-9 \), find an expression that equals \( 2 C-D \) in standard fo Answer Attempt 1 out of 2

Ask by Ward Ortiz. in the United States
Feb 03,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

The expression \( 2C - D \) simplifies to \( -y^2 + 3y + 19 \).

Solution

To find the expression that equals \( 2C - D \), we will follow these steps: 1. Substitute the expressions for \( C \) and \( D \) into the equation. 2. Simplify the resulting expression. Given: - \( C = y + 5 \) - \( D = y^2 - y - 9 \) Now, let's calculate \( 2C - D \): \[ 2C = 2(y + 5) = 2y + 10 \] Next, we substitute \( D \): \[ D = y^2 - y - 9 \] Now, we can find \( 2C - D \): \[ 2C - D = (2y + 10) - (y^2 - y - 9) \] Now, let's simplify this expression step by step: 1. Distribute the negative sign across \( D \): \[ 2C - D = 2y + 10 - y^2 + y + 9 \] 2. Combine like terms: - Combine \( 2y \) and \( y \): \[ 2y + y = 3y \] - Combine \( 10 \) and \( 9 \): \[ 10 + 9 = 19 \] Putting it all together, we have: \[ 2C - D = -y^2 + 3y + 19 \] Now, let's express this in standard form, which is typically written with the highest degree term first: \[ 2C - D = -y^2 + 3y + 19 \] Thus, the final expression that equals \( 2C - D \) in standard form is: \[ -y^2 + 3y + 19 \]

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Simplify this solution

Beyond the Answer

Let's break it down and find the expression for \( 2C - D \). First, we have \( C = y + 5 \), so: \[ 2C = 2(y + 5) = 2y + 10 \] Now, using \( D = y^2 - y - 9 \), we proceed to calculate \( 2C - D \): \[ 2C - D = (2y + 10) - (y^2 - y - 9) \] Distributing the negative sign: \[ = 2y + 10 - y^2 + y + 9 \] Combining like terms: \[ = -y^2 + 3y + 19 \] So, the expression that equals \( 2C - D \) in standard form is: \[ -y^2 + 3y + 19 \] Now you've got a snazzy polynomial ready for just about any algebraic adventure!

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