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a) \( \frac{3}{7}+\left(\frac{f}{4}\right)^{3} \)

Ask by Carrillo Peterson. in Colombia
Feb 03,2025

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Answer

La expresión simplificada es \( \frac{192 + 7f^{3}}{448} \).

Solution

Claro, simplifiquemos la expresión dada paso a paso: a) \( \frac{3}{7} + \left( \frac{f}{4} \right)^{3} \) 1. **Calcular el exponente:** Primero, elevamos \( \frac{f}{4} \) al cubo: \[ \left( \frac{f}{4} \right)^{3} = \frac{f^{3}}{4^{3}} = \frac{f^{3}}{64} \] 2. **Sumar las fracciones:** Ahora, sumamos \( \frac{3}{7} \) y \( \frac{f^{3}}{64} \): \[ \frac{3}{7} + \frac{f^{3}}{64} \] Para sumar estas dos fracciones, necesitamos un denominador común. El mínimo común múltiplo (MCM) de 7 y 64 es 448. Convertimos cada fracción al denominador común: \[ \frac{3}{7} = \frac{3 \times 64}{7 \times 64} = \frac{192}{448} \] \[ \frac{f^{3}}{64} = \frac{f^{3} \times 7}{64 \times 7} = \frac{7f^{3}}{448} \] 3. **Sumar las fracciones con el mismo denominador:** \[ \frac{192}{448} + \frac{7f^{3}}{448} = \frac{192 + 7f^{3}}{448} \] Por lo tanto, la expresión simplificada es: \[ \frac{192 + 7f^{3}}{448} \]

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The Deep Dive

To tackle the expression \( \frac{3}{7} + \left(\frac{f}{4}\right)^{3} \), it's important to remember how to work with fractions and exponents. The term \( \left(\frac{f}{4}\right)^{3} \) means you first take \( \frac{f}{4} \) and multiply it by itself three times, yielding \( \frac{f^3}{4^3} = \frac{f^3}{64} \). So your expression can be rewritten as \( \frac{3}{7} + \frac{f^3}{64} \). To combine these fractions, you'll need a common denominator, which in this case would be 448 (the least common multiple of 7 and 64). For combining the fractions, we'll convert each term: 1. \( \frac{3}{7} \) becomes \( \frac{3 \times 64}{7 \times 64} = \frac{192}{448} \). 2. \( \frac{f^3}{64} \) becomes \( \frac{f^3 \times 7}{64 \times 7} = \frac{7f^3}{448} \). Now you can add them up: \[ \frac{192}{448} + \frac{7f^3}{448} = \frac{192 + 7f^3}{448}. \] So the final simplified expression is \( \frac{192 + 7f^3}{448} \).

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