Question
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The vapour pressure of a liquid at 20 deg C is 0.57 atm but it raises to 0.65 at when the
temperature raises by 3 deg C . Calculate the enthalpy of vaporisation of this liquid (in
).

Ask by Schofield Reid. in Guyana
Nov 30,2024

Upstudy AI Solution

Tutor-Verified Answer

Answer

The enthalpy of vaporization of the liquid is approximately 42.12 kJ/mol.

Solution

To calculate the enthalpy of vaporization ( ) of the liquid, we can use the Clausius-Clapeyron equation, which relates the change in vapor pressure with temperature to the enthalpy of vaporization:
Where:
  • and are the vapor pressures at temperatures and respectively.
  • is the universal gas constant, approximately .
  • and are the absolute temperatures in Kelvin.
Given:
  • at
  • at
Now, we can plug in the values into the Clausius-Clapeyron equation:
  1. Calculate :
  1. Calculate :
  1. Substitute these values into the Clausius-Clapeyron equation:
  1. Rearranging to solve for :
  1. Calculate :
Thus, the enthalpy of vaporization of the liquid is approximately:

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Simplify this solution

Beyond the Answer

To calculate the enthalpy of vaporization ( ) of the liquid, we can use the Clausius-Clapeyron equation given by:
Where:
  • (pressure at )
  • (pressure at )
First, we convert the pressures to a natural logarithm:
Now, substituting the values into the Clausius-Clapeyron equation:
Now calculate the difference in the inverse of temperatures:
Thus, substituting this into the equation gives:
Now we can rearrange to find :
So, the enthalpy of vaporization of the liquid is approximately 29.47 kJ/mol.

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