Question
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Write the standard form of the equation of the circle with the given center and radius. Center \( (0,0), \mathrm{r}=4 \) The equation for the circle in standard form is (Simplify your answer.)

Ask by Bob Hart. in the United States
Feb 03,2025

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Tutor-Verified Answer

Answer

The standard form of the equation of the circle is \( x^2 + y^2 = 16 \).

Solution

To write the standard form of the equation of a circle, we'll use the following formula: \[ (x - h)^2 + (y - k)^2 = r^2 \] where \((h, k)\) is the center of the circle and \(r\) is its radius. **Given:** - Center \((h, k) = (0, 0)\) - Radius \(r = 4\) **Step 1: Substitute the given values into the formula.** \[ (x - 0)^2 + (y - 0)^2 = 4^2 \] **Step 2: Simplify the equation.** \[ x^2 + y^2 = 16 \] **Final Answer:** \[ x^2 + y^2 = 16 \] This is the standard form of the equation of the circle with center at the origin \((0, 0)\) and a radius of \(4\).

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The equation for a circle in standard form is given by \( (x - h)^2 + (y - k)^2 = r^2 \), where \((h,k)\) is the center and \(r\) is the radius. For your circle with center \( (0,0) \) and radius \( 4 \), this becomes \( (x - 0)^2 + (y - 0)^2 = 4^2 \). Simplifying this, we have \( x^2 + y^2 = 16 \). So, the equation of the circle in standard form is \( x^2 + y^2 = 16 \).

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