Question
Write the standard form of the equation of the circle with the given center and radius. Center \( (0,0), \mathrm{r}=4 \) The equation for the circle in standard form is (Simplify your answer.)
Ask by Bob Hart. in the United States
Feb 03,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
The standard form of the equation of the circle is \( x^2 + y^2 = 16 \).
Solution
To write the standard form of the equation of a circle, we'll use the following formula:
\[
(x - h)^2 + (y - k)^2 = r^2
\]
where \((h, k)\) is the center of the circle and \(r\) is its radius.
**Given:**
- Center \((h, k) = (0, 0)\)
- Radius \(r = 4\)
**Step 1: Substitute the given values into the formula.**
\[
(x - 0)^2 + (y - 0)^2 = 4^2
\]
**Step 2: Simplify the equation.**
\[
x^2 + y^2 = 16
\]
**Final Answer:**
\[
x^2 + y^2 = 16
\]
This is the standard form of the equation of the circle with center at the origin \((0, 0)\) and a radius of \(4\).
Reviewed and approved by the UpStudy tutoring team
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Mind Expander
The equation for a circle in standard form is given by \( (x - h)^2 + (y - k)^2 = r^2 \), where \((h,k)\) is the center and \(r\) is the radius. For your circle with center \( (0,0) \) and radius \( 4 \), this becomes \( (x - 0)^2 + (y - 0)^2 = 4^2 \). Simplifying this, we have \( x^2 + y^2 = 16 \). So, the equation of the circle in standard form is \( x^2 + y^2 = 16 \).