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\( \begin{array}{ll}\text { ea. } \frac{3}{4}-\frac{1}{4} \cdot\left(\frac{3}{5}-\frac{1}{10}\right) & \frac{3}{8}-\frac{1}{4}:\left(\frac{2}{3} \cdot \frac{3}{4}\right) \\ \text { l. } 5+\frac{7}{3}:\left(\frac{4}{3}+2\right) & \text { d. } \frac{8}{3}-\left(\frac{1}{3}+\frac{1}{2}\right): \frac{5}{4}\end{array} \)

Ask by Hardy Clark. in Spain
Feb 03,2025

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**Resultados:** - **ea.** \( \frac{5}{8} \) - **Sin etiqueta.** \( -\frac{1}{8} \) - **l.** \( \frac{57}{10} \) o \( 5.7 \) - **d.** \( 2 \)

Solution

Claro, a continuación se resuelven las expresiones proporcionadas: ### ea. \( \frac{3}{4} - \frac{1}{4} \cdot \left( \frac{3}{5} - \frac{1}{10} \right) \) **Solución:** \[ \begin{align*} \frac{3}{4} - \frac{1}{4} \cdot \left( \frac{3}{5} - \frac{1}{10} \right) &= \frac{3}{4} - \frac{1}{4} \cdot \left( \frac{6}{10} - \frac{1}{10} \right) \\ &= \frac{3}{4} - \frac{1}{4} \cdot \frac{5}{10} \\ &= \frac{3}{4} - \frac{1}{8} \\ &= \frac{6}{8} - \frac{1}{8} \\ &= \frac{5}{8} \end{align*} \] **Resultado:** \( \frac{5}{8} \) --- ### \( \frac{3}{8} - \frac{1}{4} : \left( \frac{2}{3} \cdot \frac{3}{4} \right) \) **Solución:** \[ \begin{align*} \frac{3}{8} - \frac{1}{4} : \left( \frac{2}{3} \cdot \frac{3}{4} \right) &= \frac{3}{8} - \frac{1}{4} \div \left( \frac{6}{12} \right) \\ &= \frac{3}{8} - \frac{1}{4} \div \frac{1}{2} \\ &= \frac{3}{8} - \left( \frac{1}{4} \times 2 \right) \\ &= \frac{3}{8} - \frac{2}{4} \\ &= \frac{3}{8} - \frac{1}{2} \\ &= \frac{3}{8} - \frac{4}{8} \\ &= -\frac{1}{8} \end{align*} \] **Resultado:** \( -\frac{1}{8} \) --- ### l. \( 5 + \frac{7}{3} : \left( \frac{4}{3} + 2 \right) \) **Solución:** \[ \begin{align*} 5 + \frac{7}{3} : \left( \frac{4}{3} + 2 \right) &= 5 + \frac{7}{3} \div \left( \frac{4}{3} + \frac{6}{3} \right) \\ &= 5 + \frac{7}{3} \div \frac{10}{3} \\ &= 5 + \left( \frac{7}{3} \times \frac{3}{10} \right) \\ &= 5 + \frac{21}{30} \\ &= 5 + \frac{7}{10} \\ &= 5.7 \\ &= \frac{57}{10} \end{align*} \] **Resultado:** \( \frac{57}{10} \) o \( 5.7 \) --- ### d. \( \frac{8}{3} - \left( \frac{1}{3} + \frac{1}{2} \right) : \frac{5}{4} \) **Solución:** \[ \begin{align*} \frac{8}{3} - \left( \frac{1}{3} + \frac{1}{2} \right) : \frac{5}{4} &= \frac{8}{3} - \left( \frac{2}{6} + \frac{3}{6} \right) \div \frac{5}{4} \\ &= \frac{8}{3} - \frac{5}{6} \div \frac{5}{4} \\ &= \frac{8}{3} - \left( \frac{5}{6} \times \frac{4}{5} \right) \\ &= \frac{8}{3} - \frac{20}{30} \\ &= \frac{8}{3} - \frac{2}{3} \\ &= \frac{6}{3} \\ &= 2 \end{align*} \] **Resultado:** \( 2 \) --- **Resumen de Resultados:** - **ea.** \( \frac{5}{8} \) - **Sin etiqueta.** \( -\frac{1}{8} \) - **l.** \( \frac{57}{10} \) o \( 5.7 \) - **d.** \( 2 \)

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Let's break down some tasty knowledge, shall we? Did you know that fractions have a rich history dating back to ancient civilizations, including the Egyptians and Babylonians? They needed fractions for trade and agriculture, creating early techniques for division that are still foundational today. The symbol we often use for fractions, like denominators and numerators, became standardized in Europe during the Middle Ages. Quite a journey for our friendly little numbers! Now, if you’re wrangling fractions, here’s a nifty tip: Always convert your fractions to the same denominator before performing subtraction or addition. A common pitfall is jumping right into calculations without aligning those denominators, which can lead to mistakes and even a wrong answer! So take that extra moment; your future math-loving self will thank you!

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