Question
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Find the cube root of the following using prime factorization. Leave your answer in index notation. (a) \( 2^{\wedge} 3 \times 5^{\wedge} 6 \) (b) \( 3^{\wedge} 3 \times 5^{\wedge} 9 \times 7^{\wedge} 6 \)

Ask by Chen Chang. in Singapore
Jan 23,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

(a) \( 2 \times 5^{2} \) (b) \( 3 \times 5^{3} \times 7^{2} \)

Solution

To find the cube roots of the given expressions using prime factorization and express the answers in index notation, follow these steps: ### (a) \( 2^{3} \times 5^{6} \) 1. **Apply the cube root to each factor:** \[ \sqrt[3]{2^{3} \times 5^{6}} = \sqrt[3]{2^{3}} \times \sqrt[3]{5^{6}} \] 2. **Simplify each cube root:** \[ \sqrt[3]{2^{3}} = 2^{3/3} = 2^{1} = 2 \] \[ \sqrt[3]{5^{6}} = 5^{6/3} = 5^{2} \] 3. **Combine the simplified terms:** \[ 2 \times 5^{2} \] **Final Answer for (a):** \[ 2 \times 5^{2} \] --- ### (b) \( 3^{3} \times 5^{9} \times 7^{6} \) 1. **Apply the cube root to each factor:** \[ \sqrt[3]{3^{3} \times 5^{9} \times 7^{6}} = \sqrt[3]{3^{3}} \times \sqrt[3]{5^{9}} \times \sqrt[3]{7^{6}} \] 2. **Simplify each cube root:** \[ \sqrt[3]{3^{3}} = 3^{3/3} = 3^{1} = 3 \] \[ \sqrt[3]{5^{9}} = 5^{9/3} = 5^{3} \] \[ \sqrt[3]{7^{6}} = 7^{6/3} = 7^{2} \] 3. **Combine the simplified terms:** \[ 3 \times 5^{3} \times 7^{2} \] **Final Answer for (b):** \[ 3 \times 5^{3} \times 7^{2} \]

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To find the cube root of the given expressions using prime factorization, we can express the original expressions in index notation, then apply the cube root to each term. (a) Given \( 2^{3} \times 5^{6} \): 1. First, break down \( 5^{6} \). We can rewrite it as \( (5^{2})^{3} \). 2. Thus, we have: \( 2^{3} \times (5^{2})^{3} \). 3. Now, applying the cube root: \( \sqrt[3]{2^{3} \times (5^{2})^{3}} = 2^{1} \times 5^{2} = 2 \times 25 = 50 \). So, in index notation, the cube root is \( 2^{1} \times 5^{2} \). (b) Given \( 3^{3} \times 5^{9} \times 7^{6} \): 1. We can rewrite \( 5^{9} \) as \( (5^{3})^{3} \) and \( 7^{6} \) as \( (7^{2})^{3} \). 2. Thus, we have: \( (3^{3})^{1} \times (5^{3})^{3} \times (7^{2})^{3} \). 3. Applying the cube root: \( \sqrt[3]{3^{3} \times (5^{3})^{3} \times (7^{2})^{3}} = 3^{1} \times 5^{3} \times 7^{2} \). In index notation, the cube root is \( 3^{1} \times 5^{3} \times 7^{2} \).

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