Find the cube root of the following using prime factorization. Leave your answer in index notation. (a) \( 2^{\wedge} 3 \times 5^{\wedge} 6 \) (b) \( 3^{\wedge} 3 \times 5^{\wedge} 9 \times 7^{\wedge} 6 \)
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To find the cube root of the given expressions using prime factorization, we can express the original expressions in index notation, then apply the cube root to each term. (a) Given \( 2^{3} \times 5^{6} \): 1. First, break down \( 5^{6} \). We can rewrite it as \( (5^{2})^{3} \). 2. Thus, we have: \( 2^{3} \times (5^{2})^{3} \). 3. Now, applying the cube root: \( \sqrt[3]{2^{3} \times (5^{2})^{3}} = 2^{1} \times 5^{2} = 2 \times 25 = 50 \). So, in index notation, the cube root is \( 2^{1} \times 5^{2} \). (b) Given \( 3^{3} \times 5^{9} \times 7^{6} \): 1. We can rewrite \( 5^{9} \) as \( (5^{3})^{3} \) and \( 7^{6} \) as \( (7^{2})^{3} \). 2. Thus, we have: \( (3^{3})^{1} \times (5^{3})^{3} \times (7^{2})^{3} \). 3. Applying the cube root: \( \sqrt[3]{3^{3} \times (5^{3})^{3} \times (7^{2})^{3}} = 3^{1} \times 5^{3} \times 7^{2} \). In index notation, the cube root is \( 3^{1} \times 5^{3} \times 7^{2} \).