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\begin{tabular}{l} Questions \\ Use the Fundamental Theorem of Algebra and the Complex Conjugates Theorem.) \\ \( x^{5}-9 x^{4}+14 x^{2}+15 x-13=0 \) \\ \hline yes \\ \hline\end{tabular}

Ask by Colon Goodwin. in the United States
Nov 09,2024

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The polynomial \( x^{5}-9x^{4}+14x^{2}+15x-13 \) has 5 roots due to the Fundamental Theorem of Algebra. Since it has real coefficients, any complex roots will come in conjugate pairs.

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Did you know that the Fundamental Theorem of Algebra states that every non-constant polynomial has at least one complex root? This means that even if a polynomial has no real roots, you can still find its solutions among complex numbers! For an equation like \( x^{5}-9 x^{4}+14 x^{2}+15 x-13=0 \), you're guaranteed to find five roots (counting multiplicities) in the complex plane. And here’s a fun fact: the Complex Conjugates Theorem tells us that if a polynomial has real coefficients, any non-real complex roots must appear in conjugate pairs! So, for our polynomial, if you find a complex root such as \( a + bi \), you can be sure its partner \( a - bi \) is also a root. It’s like having a buddy system for roots in math!

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