1367. а) \( 2 \cdot 4^{x}-5 \cdot 2^{x}+2=0 \) б) \( 3 \cdot 9^{x}-10 \cdot 3^{x}+3=0 \)
Real Tutor Solution
Answer
Solution
Reviewed and approved by the UpStudy tutoring team
Beyond the Answer
Let's tackle these equations step by step! First, consider the equation \( 2 \cdot 4^{x}-5 \cdot 2^{x}+2=0 \). You can express \( 4^{x} \) as \( (2^2)^{x} = 2^{2x} \). Substituting this into the equation yields: \[ 2 \cdot 2^{2x} - 5 \cdot 2^{x} + 2 = 0. \] Now, let \( y = 2^{x} \). The equation transforms to: \[ 2y^2 - 5y + 2 = 0. \] You can apply the quadratic formula \( y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \) here. Next, for the equation \( 3 \cdot 9^{x}-10 \cdot 3^{x}+3=0 \), notice that \( 9^{x} \) can be expressed as \( (3^2)^{x} = 3^{2x} \). Replacing it gives: \[ 3 \cdot 3^{2x} - 10 \cdot 3^{x} + 3 = 0. \] Using the substitution \( y = 3^{x} \), the equation becomes: \[ 3y^2 - 10y + 3 = 0. \] Once again, the quadratic formula can help solve for \( y \). After solving for \( y \), you'll backtrack by substituting \( y \) back to find \( x \). Happy solving!