Franklin Chambers
11/09/2023 · High School
3. Use the value of the first integral \( I \) to evaluate the two given integrals. \( I=\int_{0}^{3}\left(x^{3}-4 x\right) d x=\frac{9}{4} \) a. \( \int_{0}^{3}\left(24 x-6 x^{3}\right) d x \) a. \( \int_{0}^{3}\left(24 x-6 x^{3}\right) d x=\frac{-27}{2} \) (Simplify your answer.) \( \int_{3}^{0}\left(4 x-x^{3}\right) d x \) b. \( \int_{3}^{0}\left(4 x-x^{3}\right) d x=\square \frac{9}{4} \) (Simplify your answer.)
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\[ \int_{3}^{0} \left( 4x - x^3 \right) dx = \frac{9}{4} \]
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