Davies Rodriguez
12/28/2023 · High School

I/ On donne : \( 2,15 \leq x \leq 2,18 \). Détermine une valeur approchée de \( x \), en précisant son incertitude. II/ Ecris les nombres réels suivants sans le symbole de la valeur absolue. (2pts) \( |\sqrt{2}-1| ;|5-\sqrt{19}| ; \quad|-3+\sqrt{17}| ; \quad\left|\frac{3}{7}-\frac{7}{3}\right| \) III Soit deux réels \( x \) et y strictement positifs. (2pts) \( \begin{array}{ll}\text { 1) Développer }(x+y)^{2} . & \text { 2) Démontrer que } \frac{1}{x^{2}+y^{2}} \leq \frac{1}{2 x y} .\end{array} \)

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**I/ Valeur approchée de \( x \) avec incertitude** - **Valeur centrale** : 2,165 - **Incertitude** : 0,015 Donc, \( x \approx 2,165 \pm 0,015 \) --- **II/ Écriture sans valeur absolue** 1. \( |\sqrt{2} - 1| = \sqrt{2} - 1 \) 2. \( |5 - \sqrt{19}| = 5 - \sqrt{19} \) 3. \( |-3 + \sqrt{17}| = -3 + \sqrt{17} \) 4. \( \left|\frac{3}{7} - \frac{7}{3}\right| = \frac{7}{3} - \frac{3}{7} \) --- **III/ Propriétés des réels \( x \) et \( y \) strictement positifs** 1. \( (x + y)^2 = x^2 + 2xy + y^2 \) 2. \( \frac{1}{x^{2}+y^{2}} \leq \frac{1}{2xy} \) car \( x^2 + y^2 \geq 2xy \) pour tous \( x, y > 0 \).

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