Determine whether the following statement makes sense or does not make sense. Although the data set \( 5,5,6,6,6,7,7,7 \) has a number of repeated items, there is only one mode. Choose the correct answer below. A. The statement does not make sense because there are no modes in the data set. B. The statement makes sense because there is 1 mode in the data set. C. The statement does not make sense because every value is a mode in the data set. D. The statement does not make sense because there are 2 modes in the data set.

Here are the weights (in pounds) of a sample of 8 male eleventh grade \( 146,153,172,157,161,165,165,161 \) Send data to calculator Find the median weight of these students.

\%- canvas.strayer.edu/courses/15779/assignments/824017?module_item_id=1218797 Not Found Scenario: Customers at II Phone Call Center have been complaining that they are waiting too long for service. Ihe managers do some investigating to determine the typical service time for their customers for morning shifts compared to evening shifts - Morning shifts: \( 7,14,15,17,17,19,20,20,20,55 \) - Evening shifts: \( 2,10,11,13,21,21,29,32,33,46 \) A. Calculate the mean, median, and mode for each shift using the data above. Explain your calculations. B. Determine which descriptive statistic (mean, median, or mode) you would utilize to communicate the typical service time explanation, be sure to include which shift (morning or evening) has the quicker turn-around time. Note: This assignment does not require research, but if you choose to use information from a source, be sure to cite it. Standards (SWS). The library is your home for SWS assistance, including citations and formatting. Please refer to the Lit any additional instructions.

recent survey, 8 college graduates were each asked for the number of hours they work each week. Here \( 56,40,43,38,46,38,50,53 \) the range of the data set.

1. A US Travel Data Center survey conducted of 1500 People found that 585 people Said that they would take more vacations this year than last Year. Find: a. The \( 95 \% \) confidence interval for the true proportion of people who said they wou b. \( \begin{array}{l}\text { travel more this year. } 99 \% \text { confidence interval for the true proportion of people who said they wou } \\ \text { travel more this year. }\end{array} \) c. The \( 90 \% \) confidence interval for the true proportion of people who said they wou travel more this year.

Se realizará un estudio sobre los promedios de estudiantes de preparatoria en una población de 9560 estudiantes. Se requiere un nivel de confianza del \( 99 \% \) y se estima un error del \( 4 \% \).