Welch Burton
10/26/2024 · Junior High School

Si \[ f(x)=\left\{\begin{array}{ll}x^{2} \sin \left(x^{-1}\right)+\frac{1}{2} x & \text { si } x \neq 0 \\ 0 & \text { si } x=0\end{array}\right. \] (a) Demostrar que \( f^{\prime}(0)>0 \) (b) Demostrar que \( f(x) \) no es creciente en cualquier intervalo abierto que contiene al cero.

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(a) **Demostración de que \( f^{\prime}(0) > 0 \)** Calculamos la derivada de \( f \) en \( x = 0 \): \[ f^{\prime}(0) = \lim_{x \to 0} \frac{f(x)}{x} = \lim_{x \to 0} \left( x \sin\left(\frac{1}{x}\right) + \frac{1}{2} \right) = \frac{1}{2} > 0 \] (b) **Demostración de que \( f(x) \) no es creciente en ningún intervalo abierto que contenga el cero** En cualquier vecindad de \( x = 0 \), la función \( f(x) \) oscila debido al término \( x^{2} \sin\left(\frac{1}{x}\right) \). Esto significa que \( f(x) \) aumenta y disminuye en intervalos cercanos a \( 0 \), por lo que no es creciente en ningún intervalo abierto que incluya \( 0 \).

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