Assume that a sample is used to estimate a population proportion p. Find the \( 98 \% \) confidence interval for a sample of size 228 with \( 75.9 \% \) successes. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places. \( 98 \% \) C.I. - Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.

In a normal distribution, a data value located 1.2 standard deviations below the mean has Standard Score: \( \mathrm{z}=\square \) In a normal distribution, a data value located 2.4 standard deviations above the mean has Standard Score: \( \mathrm{z}=\square \) In a normal distribution, the mean has Standard Score: \( \mathrm{z}=\square \)

Consider the Standard Normal distribution. The mean is always \( \square \) and the standard deviation is always

A set of exam scores is normally distributed with a mean \( =74 \) and standard deviation \( =8 \). \( 95 \% \) of the data values lie between 58 \( \% \) of the exam scores are between 66 and 74 . \( \% \) of the exam scores are between 74 and 90 . \% of the exam scores are greater than or equal to 66 .

Which of the following statements are TRUE about the Normal Distribution? Check all that apply. The graph of the Normal Distribution is bell-shaped, with tapering tails that never actually touch the horizontal axis. \( 50 \% \) of the data values lie at or above the mean. about \( 95 \% \) of all data values lie within 1 standard deviation of the mean. The mean, median and mode are all equal and occur at the center of the distribution. Data values are spread evenly around the mean. Data values farther from the mean are less common than data values closer to the mean.

In a normal distribution, a data value located 1.4 standard deviations below the mean has Standard Score: \( \mathrm{z}=-1.4 \) In a normal distribution, a data value located 2.3 standard deviations above the mean has Standard Score: \( \mathrm{z}=2.3 \) In a normal distribution, the mean has Standard Score: \( \mathrm{z}=\square \)