Salazar Vaughan
05/20/2024 · High School
0. Tye algebraic expressions are given below. \[ \left(2 x^{2}+7 x-4\right) \text { and }(x-3) \] xat Divide \( \left(2 x^{2}+7 x-4\right) \) by \( (x-3) \) (b) For what value replaced in 4 of the above expression, the remainder is equal to 0 ?
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When dividing \(2x^2 + 7x - 4\) by \(x - 3\), the quotient is \(2x + 13\) and the remainder is 35. There is no value of \(x\) that makes the remainder equal to 0.
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