Determine the location and value of the absolute extreme values of $$ f $$ on the given interval, if they exist. $$ f(x)=\frac{8 x^{3}}{3}+5 x^{2}-12 x $$ on $$ [-3,1] $$

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Luna Nunez · Accepted Answer

The absolute maximum value of $$ f $$ is $$ \frac{68}{3} $$ at $$ x = -2 $$, and the absolute minimum value is $$ -\frac{81}{16} $$ at $$ x = \frac{3}{4} $$.

Determine the location and value of the absolute extreme values of \( f \) on the given interval, if they exist. \( f(x)=\frac{8 x^{3}}{3}+5 x^{2}-12 x \) on \( [-3,1] \)

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Determine the location and value of the absolute extreme values of \( f \) on the given interval, if they exist. \( f(x)=\frac{8 x^{3}}{3}+5 x^{2}-12 x \) on \( [-3,1] \)

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