\( \left\{\begin{array}{l}\text { Реши систему неравенств: } \\ (5 x+10)-5 \cdot(x+5)>5 x \\ (x-3)(x+8)<0\end{array}\right. \)

6. Simplify these expressions and find then values if \( x=3, p=-1,4=-2 \) (i) \( 3 p+4+2 q+1 \) (ii) \( 8-6 x+4 x+3 \)

Exercise 3.17 Determine if each one of the following system of linear equations has unique solution, no solution or infinitely many solutions. \( \begin{array}{ccc}x-y=1 & \text { b. } \begin{array}{c}x+y=1 \\ 2 x+3 y=4\end{array} & \begin{array}{c}x-2 y=1 \\ x+y=5\end{array} \\ \begin{array}{l}\text { a. } \\ x+4 y=2\end{array}\end{array} \)

(iii) \( -2 p^{3}-3 p^{2}+4 p+7 \)

b. प्रमाणित गर्नुहोस् (Prove that): \( \frac{1}{1-\mathrm{x}^{\mathrm{a}-\mathrm{b}}}+\frac{1}{1-\mathrm{x}^{\mathrm{b}-\mathrm{a}}}=1 \)

\( f(x)=\frac{x+k}{x-1} \) and \( (5,2) \in f^{-1} \), then \( K= \)