Find the function value using coordinates of points on the unit circle. Give an exact answer. \( \cos \frac{11 \pi}{6} \) Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. \( \cos \frac{11 \pi}{6}=\square \) (Simplify your answer, including any radicals. Use integers or'fractions for any numbers in theraxpression.) B. The function is undefined.

If \( x \) is in the third quadrant, then \( \cot x \) in terms of \( \sec x \) is A) \( \frac{\sqrt{\sec ^{2} x-1}}{\sec ^{2} x-1} \) B) \( -\frac{\sqrt{\sec ^{2} x-1}}{\sec ^{2} x-1} \) C) \( -\frac{\sqrt{\sec ^{2} x+1}}{\sec ^{2} x-1} \)

If \( \csc \theta=\frac{x+1}{x}, x>0 \), then \( \cot \theta= \)

If \( \sec (3 \theta+15)=\csc (35-\theta) \) where \( \theta \) is an acute angle, then \( \csc \frac{3}{2} \theta=\cdots \) \( \begin{array}{llll}\text { (a) } 2 & \text { (b) } \sqrt{3} & \text { (c) } \sqrt{2} & \text { (d) } \frac{1}{2}\end{array} \)

11) The measure of the smallest positive angle satisfy the relation : \( 2 \sin \theta=-1 \) is \( \begin{array}{lll}\text { (a) } 30^{\circ} & \text { (b) } 120^{\circ} & \text { (c) } 210^{\circ} y=x\end{array} \)

Exercice 1: D. Ecrirc sous forme trigonométrique : \( z_{1}=2\left(\cos \frac{\pi}{4}-i \sin \frac{\pi}{4}\right) \) \( \begin{array}{ll}z_{2}=-3\left(\cos \frac{2 \pi}{3}+i \sin \frac{2 \pi}{3}\right) \quad z_{3}=2\left(\cos \frac{\pi}{4}+i \sin \frac{3 \pi}{4}\right) \\ z_{4}=\cos \frac{\pi}{6}+i \sin \left(-\frac{\pi}{6}\right) \quad z_{5}=\cos \theta-i \sin \theta \quad z_{5}=\sin \theta+i \cos \theta\end{array} \)