Schneider Hodgson
11/29/2023 · Elementary School

2.3 The following unbalanced reaction produces 120 g of \( \mathrm{PF}_{3} \) and has a \( 78.1 \% \) yield. \[ P_{4}(s)+F_{2}(g) \rightarrow P F_{3}(g) \] 2.3.1 Write a balanced equation for this reaction. 2.3.2 Calculate the theoretical yield of \( \mathrm{PF}_{3} \) (1) 2.3.3 Calculate the mass of \( \mathrm{F}_{2} \) needed for this reaction.

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The balanced equation is \( P_{4}(s) + 6 F_{2}(g) \rightarrow 4 PF_{3}(g) \). The theoretical yield of \( PF_{3} \) is approximately 153.5 g. The mass of \( F_{2} \) needed is approximately 99.3 g.

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