a) Sketch the curve with equation $$ y=a^{-x}+4 $$ where $$ a $$ is a constant and $$ a1 $$ On your sketch show

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a) Sketch the curve with equation $$ y=a^{-x}+4 $$ where $$ a $$ is a constant and $$ a>1 $$ On your sketch show

Ayala Weaver · Accepted Answer

To sketch the curve $$ y = a^{-x} + 4 $$ where $$ a > 1 $$, follow these steps: 1. **Horizontal Asymptote:** Draw a dashed line at $$ y = 4 $$. 2. **Y-Intercept:** Plot the point $$ (0, 5) $$. 3. **Additional Points:** Plot points like $$ (1, 4.5) $$ and $$ (-1, 6) $$ for $$ a = 2 $$. 4. **Shape:** Draw a smooth, decreasing curve that approaches $$ y = 4 $$ as $$ x $$ increases and rises steeply as $$ x $$ decreases. 5. **No X-Intercept:** The graph does not cross the x-axis. Include the horizontal asymptote, y-intercept, additional points, and the decreasing nature of the curve in your sketch.

a) Sketch the curve with equation \[ y=a^{-x}+4 \] where \( a \) is a constant and \( a>1 \) On your sketch show

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a) Sketch the curve with equation \[ y=a^{-x}+4 \] where \( a \) is a constant and \( a>1 \) On your sketch show

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