For the following function, a) determine whether it is one-to-one; b) if it is one-to-one, find its inverse func \( f(x)=x-6 \) Is the given function a one-to-one function? Select the correct choice below and, if necessary, fill in the at A. Yes, the function is one-to-one. The inverse function is \( \mathrm{f}^{-1}(\mathrm{x})= \) (Simplify your answer.) B. No, the the function is not one-to-one.

2imalify \( \frac{x^{2}-y^{2}}{x^{2} x y} \) \( \frac{y+2 x-3 y}{3 x-2 y}=4 \), evaluate \( 2 x y \) If \( z=\sqrt{x^{2}-y^{2}} \), express \( x \) interm 9 \( y \) and 2

ii) \( \frac{4 x^{2}+3 x+7}{x+1} \)

5. Separen en términos y resuelvan. a. \( \left(-\frac{4}{3}+\frac{1}{6}\right)-\left(-\frac{3}{2}\right)^{-2}+\sqrt[3]{\left(\frac{3}{4}+\frac{1}{8}\right)-} \) b. \( \left(\frac{3}{2}-\frac{1}{2}\right)^{2}+\sqrt[3]{-\frac{1}{64}}-0.5= \) c. \( \sqrt[3]{1-\frac{7}{8}}-\left(-\frac{2}{5}+\frac{1}{10}\right)^{-4}+0.3- \) d. \( -\left(\frac{8}{5}-\frac{6}{15}\right)-\sqrt[3]{1-\frac{31}{32}}+\left(\frac{7}{5}\right)^{2}= \)

d the exact value of the solution to the equation \( 2 e^{2 x}-7 e^{x}-4=0 \)

2.3 Express \( \frac{1}{\sqrt{2}+1} \) in its simpl