2. For the equation $$ \cos 2 x=-0.32 $$ a) solve for $$ x $$, where $$ 0 \leq x

Question

2. For the equation $$ \cos 2 x=-0.32 $$ a) solve for $$ x $$, where $$ 0 \leq x<2 \pi $$ $$ \arccos (-0.32) \approx 1.8925 $$ radialls $$ 2 \pi-1.8925 \approx 4.3907 $$ b) determine the general solution.

Reid Reyes · Accepted Answer

The solutions for $$ x $$ are approximately $$ x \approx 0.9463 $$ radians and $$ x \approx 2.1953 $$ radians. The general solutions are $$ x \approx 0.9463 + \pi n $$ and $$ x \approx 2.1953 + \pi n $$ for any integer $$ n $$.

2. For the equation \( \cos 2 x=-0.32 \) a) solve for \( x \), where \( 0 \leq x<2 \pi \) \( \arccos (-0.32) \approx 1.8925 \) radialls \[ 2 \pi-1.8925 \approx 4.3907 \] b) determine the general solution.

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2. For the equation \( \cos 2 x=-0.32 \) a) solve for \( x \), where \( 0 \leq x<2 \pi \) \( \arccos (-0.32) \approx 1.8925 \) radialls \[ 2 \pi-1.8925 \approx 4.3907 \] b) determine the general solution.

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