An automobile manufacturer has given its van a 31.0 miles/gallon (MPG) rating. An Independent testing firm has been contracted to test the actual MPG for thls van since it is belleved that the van performs under the manufacturer's MPG rating. After testing 150 vans, they found a mean MPG of 30.8. Assume the population standard deviation is known to be 2.1. Is there sufficient evidence at the 0.02 level to support the testing firm's claim? Step 1 of 6: State the null and alternative hypotheses. Answer 2 Points

\( 11,16,12,7,23,9,5,5 \) What is the median of the data? B. 10 D. 11 D. 18

\( n = 5 \quad p ( \overline { x } > 500 ) \)

Use this set of numbers to answer the question. \( \begin{array}{l}4,11,6,9,23,34,6,19 \\ \text { What is the median for this set of numbers? } \\ \text { A. } 6 \\ \text { B. } 10 \\ \text { D. } 14 \\ \text { D. } 16\end{array} \)

Josie is organizing her ribbons for a craft project. The list shows the length of each of her ribbons. \( 21.5 \mathrm{~cm}, 12.4 \mathrm{~cm}, 30.4 \mathrm{~cm}, 15.3 \mathrm{~cm}, 10.7 \mathrm{~cm}, 7.9 \mathrm{~cm}, 14.6 \mathrm{~cm}, 11.2 \mathrm{~cm} \) What is the median ribbon length? A. 12.4 cm B. 13.0 cm C. 13.5 cm D. 14.6 cm E. 15.5 cm

Question 2 ( 0.25 points) Retake question Choose the correct interpretation of a p-value. If the test is right-tailed, the \( p \)-value is the probability of observing a sample proportion as small as we saw in our sample, if the null hypothesis were true. If the test is right-tailed, the \( p \)-value is the probability of observing a sample proportion as large as we saw in our sample, if the null hypothesis were true. If the test is right-tailed, the \( p \)-value is the probability of observing a sample proportion as large as we saw in our sample. If the test is two-tailed, the \( p \)-value is the probability of observing a sample proportion as far away from the null value as what was observed in the current data set.