Find the equation of the line perpendicular to $$ y=2 x+5 $$ that passes through the point $$ (3,-1) $$ in slope-intercept form. a.) $$ y=2 x-7 $$ b.) $$ y=2 x-5 $$ c.) $$ y=-\frac{1}{2} x+\frac{1}{2} $$ d.) $$ y=-\frac{1}{2} x+\frac{5}{2} $$

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Frank Burton · Accepted Answer

The equation of the perpendicular line is $$ y = -\frac{1}{2}x + \frac{1}{2} $$.

Find the equation of the line perpendicular to \( y=2 x+5 \) that passes through the point \( (3,-1) \) in slope-intercept form. a.) \( y=2 x-7 \) b.) \( y=2 x-5 \) c.) \( y=-\frac{1}{2} x+\frac{1}{2} \) d.) \( y=-\frac{1}{2} x+\frac{5}{2} \)

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Find the equation of the line perpendicular to \( y=2 x+5 \) that passes through the point \( (3,-1) \) in slope-intercept form. a.) \( y=2 x-7 \) b.) \( y=2 x-5 \) c.) \( y=-\frac{1}{2} x+\frac{1}{2} \) d.) \( y=-\frac{1}{2} x+\frac{5}{2} \)

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