Tyler Bryant
11/23/2024 · High School
(a) Find the area of the region enclosed by: \[ y=\sin x \text {, and } y=2 \cos x, \quad \text { over the interval }[0, \pi] \] (b) Evaluate the following integral: \[ \int \frac{x^{3}}{\sqrt{1-x^{2}}} d x \]
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(a) The area of the region enclosed by the curves \( y = \sin x \) and \( y = 2 \cos x \) over the interval \([0, \pi]\) is \( 2\sqrt{5} \).
(b) The evaluated integral is \( -(1-x^2)^{1/2} + \frac{1}{3}(1-x^2)^{3/2} + C \).
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