Use a Riemann sum to approximate the area under the graph of $$ f(x)=4 e^{-x} $$ on the interval $$ 0 \leq x \leq 1 $$ using $$ n=5 $$ subintervals with the selected points as the right end points. The area is approximately $$ \square $$ units. (Round to six decimal places as needed.)

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Pritchard Alexander · Accepted Answer

The area under the graph of $$ f(x) = 4 e^{-x} $$ on the interval $$ [0, 1] $$ using a Riemann sum with $$ n = 5 $$ subintervals is approximately $$ 2.284000 $$ units.

Use a Riemann sum to approximate the area under the graph of \( f(x)=4 e^{-x} \) on the interval \( 0 \leq x \leq 1 \) using \( n=5 \) subintervals with the selected points as the right end points. The area is approximately \( \square \) units. (Round to six decimal places as needed.)

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Use a Riemann sum to approximate the area under the graph of \( f(x)=4 e^{-x} \) on the interval \( 0 \leq x \leq 1 \) using \( n=5 \) subintervals with the selected points as the right end points. The area is approximately \( \square \) units. (Round to six decimal places as needed.)

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