Bright Wells
01/26/2024 · Senior High School
14. A student did the following. \( \begin{aligned} \frac{d}{d x}(x) & =\frac{d}{d x}(\underbrace{1+1+1+\ldots+1}_{x \text { times }}) \\ & =0+0+0+\ldots+0 \\ & =0\end{aligned} \) What is wrong with this reasoning?
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The student incorrectly treated the sum \(1 + 1 + 1 + \ldots + 1\) as a constant, leading to the wrong conclusion that its derivative is 0. In reality, since the sum equals \(x\), the correct derivative is 1.
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