Gray Tyler
06/30/2023 · Middle School
(b) Express \( \left(\sqrt{3} \cos \theta+\sin \theta\right. \) in the form \( R \cos (\theta-\alpha) \), where \( R>0 \) and \( 0^{\circ}<\alpha<90^{\circ} \). Hence, solve the equation \( \sqrt{3} \cos \theta+\sin \theta=-1,0^{\circ}<\theta<360^{\circ} \).
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将 \( \sqrt{3} \cos \theta + \sin \theta \) 表达为 \( 2 \cos (\theta - 30^{\circ}) \)。解方程 \( \sqrt{3} \cos \theta + \sin \theta = -1 \) 在 \( 0^{\circ} < \theta < 360^{\circ} \) 的解为 \( \theta = 150^{\circ} \) 和 \( \theta = 270^{\circ} \)。
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