Morgan Olson
09/27/2023 · Senior High School

11. A particle is projected into the air at a speed of \( 25 \mathrm{~m} / \mathrm{s} \) at an angle \( 40^{\circ} \) above the horizontal. (a) How long does it take the particle to reach its maximum height? (b) What is its horizontal distance covered? 12. A stone is projected with a speed of \( 17.32 \mathrm{~m} / \mathrm{s} \) at an angle of \( 60^{\circ} \) to the horizontal. Calculate the maximum height and the range covered by the stone. 13. A ball is projected horizontally from the edge of a platform at \( 12.0 \mathrm{~m} / \mathrm{s} \). If the platform is 8.0 m above the floor, what are the magnitude and direction of the ball's velocity as it hits the floor? 14. A particle is launched such that its maximum range is 26.4 m . What is the speed at which it is launched? 15. A rifle fires a bullet at \( 360 \mathrm{~m} / \mathrm{s} \). (a) At what angle must the rifle be positioned for the bullet to hit a target 242.4 m away at the same height as the rifle?(b) If gravitational force does not act on the bullet, how far above the target will the bullet pass maintaining the same angle? 16. A particle projected at an angle of \( \theta \) above the horizontal has a velocity of \( v=(16 i+5 j) \mathrm{m} / \mathrm{s} \) at time \( t=0.8 \mathrm{~s} \) after launching. (a) What is the maximum height of the particle? (b) What is the range of the particle? 17. A ball is kicked into the air. When it reaches the vertical height of 7.5 m , the velocity is measured to have a horizontal component of \( 10.4 \mathrm{~m} / \mathrm{s} \) and a vertical component of \( 3.7 \mathrm{~m} / \mathrm{s} \). Calculate the maximum height and horizontal distance, which the ball travels.

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**Problem 11 Solutions:** **(a) Time to reach maximum height:** It takes approximately **1.64 seconds** for the particle to reach its maximum height. **(b) Horizontal distance covered:** The horizontal distance covered is approximately **31.4 meters**. If you need solutions to the other problems (12-17), feel free to ask!

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