Mathis Malone
05/05/2023 · Junior High School
№2. Решить уравнение: 3) \( 5 x-\left(3+2 x-2 x^{2}\right)=2 x^{2}-7 x+17 \), 4) \( 12-\left(3 x^{2}+5 x\right)+\left(-8 x+3 x^{2}\right)=0 \). №3. Найти значение выражения 14 \( a^{2}-\left(7 a^{2}+6 a B\right)-\left(7 a^{2}-4 a B\right) \), если \( a=-0,25, \quad B=4 \).
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### №2. Решение уравнений
#### 3) \( 5x - (3 + 2x - 2x^{2}) = 2x^{2} - 7x + 17 \)
**Шаги:**
1. Раскрыть скобки: \( 5x - 3 - 2x + 2x^{2} = 2x^{2} - 7x + 17 \)
2. Привести подобные: \( 3x + 2x^{2} - 3 = 2x^{2} - 7x + 17 \)
3. Перенести все в одну сторону: \( 10x - 20 = 0 \)
4. Решить: \( x = 2 \)
**Ответ:** \( x = 2 \)
#### 4) \( 12 - (3x^{2} + 5x) + (-8x + 3x^{2}) = 0 \)
**Шаги:**
1. Раскрыть скобки: \( 12 - 3x^{2} - 5x - 8x + 3x^{2} = 0 \)
2. Привести подобные: \( -13x + 12 = 0 \)
3. Решить: \( x = \dfrac{12}{13} \)
**Ответ:** \( x = \dfrac{12}{13} \)
### №3. Найти значение выражения
\[ 14a^{2} - (7a^{2} + 6aB) - (7a^{2} - 4aB) \]
при \( a = -0{,}25 \), \( B = 4 \).
**Шаги:**
1. Раскрыть скобки: \( 14a^{2} - 7a^{2} - 6aB - 7a^{2} + 4aB \)
2. Привести подобные: \( -2aB \)
3. Подставить значения: \( -2 \cdot (-0{,}25) \cdot 4 = 2 \)
**Ответ:** \( 2 \)
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