Dawson Todd
05/23/2024 · Primary School
Suppose \( f \) is continuous on \( [1,5] \) and the only solutions of the equation \( f(x)= \) 6 are \( x=1 \) and \( x=4 \). If \( f(2)=8 \), explain why \( f(3)>6 \). Show that \( F(x)=|x| \) is continuous evervwhere.
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\( f(3) > 6 \) because \( f \) is continuous and \( f(2) = 8 \), which is greater than 6. \( F(x) = |x| \) is continuous everywhere because it is continuous for all real numbers.
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