Ross Coleman
03/28/2024 · Junior High School
4. Solve the recurrence relation an \( -80 n-1-16 n-2 \) for \( n \geq 2, a_{0}=16, a_{1}=80 \).
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The solution to the recurrence relation is:
\[
a_n = \left(8 - \frac{70\sqrt{101}}{101}\right) \left(40 + 4\sqrt{101}\right)^n + \left(8 + \frac{70\sqrt{101}}{101}\right) \left(40 - 4\sqrt{101}\right)^n
\]
This formula gives the value of \( a_n \) for any \( n \geq 2 \) based on the initial conditions \( a_0 = 16 \) and \( a_1 = 80 \).
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